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Posted

Well, one pin is ground and the other is 5V via a 10k resistor. That'll give you 0.5mA if you connect a LED to it. Not a lot ;) If you replaced the resistor with something smaller you'll get more current, but you'll also feed the shift register... So, in short, I'd rather not do it.

Posted

Well, one pin is ground and the other is 5V via a 10k resistor. That'll give you 0.5mA if you connect a LED to it. Not a lot ;) If you replaced the resistor with something smaller you'll get more current, but you'll also feed the shift register... So, in short, I'd rather not do it.

That was clear, without cutting the tracks it wont work. But if the 5V would be sourced directly, it would be easier to provide the power for the LEDs, so no flying wires would be required....

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