Jidis Posted January 3, 2007 Report Share Posted January 3, 2007 I only see one mention of them in the Deutsch forum. Around how much are the average i/o pins looking for with stuff like this (pullups on the DINs and LED current limiters)?Just being safe. ;)George Quote Link to comment Share on other sites More sharing options...
HL-SDK Posted January 3, 2007 Report Share Posted January 3, 2007 1/8 watt is fine if they are pullup resistors.Anyone disagree? let's see... .125 is 1/8 watt so...I=V/R5V / 10000 = .0005^volts ^resistance ^currentEach resistor lets through .5mA (amirite?)P=IV.005 * 5 = .025^I ^V ^P (watts)Each resistor dissapates .025 watts, 5 times less than the max of a 1/8th wattYep. I hope. Quote Link to comment Share on other sites More sharing options...
Jidis Posted January 3, 2007 Author Report Share Posted January 3, 2007 Thanks!So I'm fine on 10k pullups then.What does the average 3 or 5mm "standard power" LED pull?(sounding lazy as s*** right now)GeorgeI'll look around a bit anyway. :) Quote Link to comment Share on other sites More sharing options...
Jidis Posted January 3, 2007 Author Report Share Posted January 3, 2007 Hey again,Around the middle of this page:http://www.opamp-electronics.com/tutorials/special_purpose_diodes_3_03_10.htmthere's a 6V LED circuit with a 220ohm, and he calculates it to 88mW and says the 1/8W is enough, so I guess I'll go with those.Take Care,George (building a giant Digikey order and a drill press and a MIDIBox simultaneously ...perhaps) Quote Link to comment Share on other sites More sharing options...
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