widdly Posted August 5, 2010 Report Share Posted August 5, 2010 Looking at different analysis of R-2R DAC's on the web, they all use a 2R for the resistor to ground. I notices in the AOut-LC it uses a 1R. Wouldn't that make the scaling of the bits all wrong? Quote Link to comment Share on other sites More sharing options...
nILS Posted August 5, 2010 Report Share Posted August 5, 2010 Yes and no. The steps aren't equally spaced with 1R to ground, that's right. Every other step is a "bit higher". It does bring the benefit of being able to have different configurations (2x8 bits that are identical, 1x12 + 1x4 bits). If you don't need the options you can easily adjust the 2 resistors to ground to get equal steps. Quote Link to comment Share on other sites More sharing options...
widdly Posted August 5, 2010 Author Report Share Posted August 5, 2010 (edited) Yes and no. The steps aren't equally spaced with 1R to ground, that's right. Every other step is a "bit higher". It does bring the benefit of being able to have different configurations (2x8 bits that are identical, 1x12 + 1x4 bits). If you don't need the options you can easily adjust the 2 resistors to ground to get equal steps. Couldn't you just add another R resistor between the ground and pin 1 and between the ground and pin 5? That way you could have both equal steps and different configurations. Edited August 5, 2010 by widdly Quote Link to comment Share on other sites More sharing options...
nILS Posted August 5, 2010 Report Share Posted August 5, 2010 Yep, that's correct. I was just assuming that what I described was TK's intention - I might be wrong with that though. Thanks for bringing it up though, I am pretty sure TK will look into it once he gets back :) Quote Link to comment Share on other sites More sharing options...
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