Artesia Posted February 15, 2006 Report Share Posted February 15, 2006 If you are new to building circuits on breadboard... or have a nightmare of a time getting a circuit layed out on one.. the following approach maybe helpful to you....the following example is of a MBHP DIN board (yup, i ran out of pre made PCB's)Firstly it is probably easiest to use the breadboard variety which has copper strips split into pad sections which cover 3 holes each.. this will save alot of cutting tracks with drills..etc. The below example did not require any track cutting.Secondly keep in mind that attempting to produce all of the connections on the breadboard itself, creates far more work, confusion & opportunity for errors than many of us have the patience for.It is best to limit the connections directly produced on the breadboard.. to those which are simple.. ie: those which occur in groups.. for instance connection points, resistor arrays, & power + data lines where viable.Here's how the DIN Board was done:Stage 1 (ic sockets & basic connections):Start by soldering the chip socekts bridging over two sets of tripads. Then solder the connection points j3 -j10 on the next set of tripads to the chips they connect to. Bridge the connections from the chips to the connection points, where they connect directly - as per circuit diagram. With regards to j1 & j2 - which carrys data + power into & out of the board; add the connection points for these right next to where they connect to, on the first & last chips (IC1 pins 9,1,2,15,16 - IC2 pins 10,1,2,15,16) (this saves alot of re-routing with cables; just for the sake of having them grouped togeather in one connector).Stage 2 (resistors & their +5v supply):With j3, j5, j7 & j9 connect the earth connection of each chip (pin 8/vss) to the respective earth pin of each 'j' connector by soldering a 'L' shape on the pads.Next solder in place all of the 'pull up' resistors r1-32 (one leg) next to the 'j' connectors. Following this connect all of the loose legs on the top side togeather in one long row (as in second picture). connnect the two rows of resistors togeather on the top side as in 2nd picture. Next solder in place r33-36 (connects to pin 10 / SER of each chip). Connect the 2nd leg of each to the top side rail created by the other resistors.Next solder a wire (use one of the resistor leg trimmings) to the resistor rail & then to pin 16 (vdd) of IC1 - this will now hook the resistors upto the +5v they need.Stage 3 (earth connections):Next connect the earth connections for j3, j5, j7 & j9 togeather with wire links. Then connect from each of these points to the earth connections for j4, j6, j8 & j10.Stage 4 (serial chain connections between chips):Connect pin 10 (ser) of IC1 to pin 9 (QH) of IC2.Connect pin 10 (ser) of IC2 to pin 9 (QH) of IC3.Connect pin 10 (ser) of IC3 to pin 9 (QH) of IC4.Stage 5 (SC & RC Connections):Connect pin 1 (LD) & 2 (CLK) (two sepperate wires) of IC1 to pin 1 & 2 of IC2. Connect pin 1&2 of IC2 to pin 1 & 2 of IC3.Connect pin 1&2 of IC3 to pin 1 & 2 of IC4.Stage 6 (capacitors):This was probably best done at stage 2 ! :)Solder in place c1-4 each connecting to pin 15 & 16 (VDD & CL1) of IC1-4.Use 100nf or so, i chose to also use one 100uf electrolytic capacitor out of my own preferences.Maybe also cover the resistors on top of the board with a strip of insulation tape to prevent +5v touching the inputs !All should now be finished ! :) Quote Link to comment Share on other sites More sharing options...
grnsky Posted January 31, 2009 Report Share Posted January 31, 2009 I'm guessing that all these steps are not needed if you have the SmashTV DIN kit? Quote Link to comment Share on other sites More sharing options...
stryd_one Posted January 31, 2009 Report Share Posted January 31, 2009 You guessed correctly :)With the smash kit you just open the bag and solder the components in the right place, that should be all. Quote Link to comment Share on other sites More sharing options...
grnsky Posted January 31, 2009 Report Share Posted January 31, 2009 Do you know then, why it seems like I am missing the 36 resistors for my DIN kit? Am I supposed to get those myself or do I not need them? Thanks Quote Link to comment Share on other sites More sharing options...
bugfight Posted January 31, 2009 Report Share Posted January 31, 2009 could it be because he supplies resistor packs (5 or 6 pin SIP) instead? Quote Link to comment Share on other sites More sharing options...
grnsky Posted January 31, 2009 Report Share Posted January 31, 2009 OOOPS! I think you're right. I was looking at the AIN kit parts. Now I am looking at the DIN kit parts I'm pretty sure and there are these little things that look like they could resistor packs. (they're like a little black hot dog with 6A103G written on them and 6 legs on the bottom). When I put these in the board everything made a LOT more sense. WHY would smash TV include all the extra holes then?? And does the resistor pack work just fine - there's DEFINITELY no need for the individual resistors?Here's what my board looks like with everything stuffed, not soldered yet. Is this right? (see image:)http://picasaweb.google.com/etbsky/Midibox#5297528954166582082 Quote Link to comment Share on other sites More sharing options...
bugfight Posted January 31, 2009 Report Share Posted January 31, 2009 thems the ones. no need for both. he sells pcbs separately as well as with kits. using both footprints allows user a choice. Quote Link to comment Share on other sites More sharing options...
JMS Posted January 31, 2009 Report Share Posted January 31, 2009 here's my version of a DINX4 on protoboard :oi built it last night in about 3 hours...... still need to mount the rest of the input terminals, but you can get the idea, right?IMG_4692.JPGIMG_4694.JPGIMG_4692.JPGIMG_4694.JPG Quote Link to comment Share on other sites More sharing options...
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