ganchan Posted April 4, 2008 Report Posted April 4, 2008 I've fried a variable psu. there was short in one cable during test.It's fired just 1 of the 2 resistors inside, the biggest one. It was connected after the rectifier at the positive pins of 2 big caps 1000µf 25v. The other resistor it's a 560ohm.It's completely fired than it's impossible to know the value. Quote
Screaming_Rabbit Posted April 4, 2008 Report Posted April 4, 2008 ... you should draw the circuit with the used parts and all the power ratings of the PSU and post it.Greats, Roger Quote
/tilted/ Posted April 5, 2008 Report Posted April 5, 2008 The resistor in question forms part of a low pass filtger, in conjunction with the two electrolytic capacitors below it.Most likely what has happened here is that when you shorted the supply, you exceeded the power rating (wattage :P) for the resistor. As this resistor is in series between the rectifier and the output, it took a whack.Do like the rabbit says. Feed us more info. Quote
ganchan Posted April 19, 2008 Author Report Posted April 19, 2008 okokok! i will post more info and a circuit schematic to help, thankyou :)for now:AC - DC AdaptorModel: AL1000/10Input: 230 ~50HzPower: 18WOutput: 1.5-3-4.5-6-7.5-9-12 V=== (the upper line it's continuous, obviously).Current: 1000mA 12VAmax. 8) Quote
/tilted/ Posted April 19, 2008 Report Posted April 19, 2008 What would help the most, would be a model number for the transformer.From this, we can determine the voltage :P taps, from them, knowing the 560R parallel value, we can determine the current limiting/low pass filtering R(x) value.Once we have done this, we (I) will suggest that you put in a higher power resistor, or do all your shorting out after a 78xx series regulator, as they have thermal cutout.... ::) Quote
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