Underskor

[SOLVED] MIOS32_AIN_CHANNEL_MASK

5 posts in this topic

Might be really obvious but it's not clicking for me.

// bit mask to enable channels

//

// Pin mapping on MBHP_CORE_STM32 module:

//   15       14      13     12     11     10      9      8   

// J16.SO  J16.SI  J16.SC J16.RC J5C.A11 J5C.A10 J5C.A9 J5C.A8

//   7        6       5      4      3      2      1       0

// J5B.A7  J5B.A6  J5B.A5 J5B.A4 J5A.A3 J5A.A2 J5A.A1  J5A.A0

//

// Examples:

//   mask 0x000f will enable all J5A channels

//   mask 0x00f0 will enable all J5B channels

//   mask 0x0f00 will enable all J5C channels

//   mask 0x0fff will enable all J5A/B/C channels

// (all channels are disabled by default)

		#define MIOS32_AIN_CHANNEL_MASK 0x0000

If 0x000f is 15, how does that relate to J5A.A0..A3?

Thanks in advance,

Tom

Edited by Underskor

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Not sure where you got 15 from?

My interpretation is:

0x0CBA

Replace the letter with 0 if you want it disabled, f for enabled. They are groups of 4 channels (eg. A0... A3)

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0x000f in decimal/base10 is 15. The reason I ask is because I'd like to disable all but the first mux (J5A.A0) so I only need to ground 7 inputs while troubleshooting/configuring.

Edited by Underskor

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It should be like this for A3...A0:


only enable A0: 1

only enable A1: 2

only enable A2: 4

only enable A3: 8


only enable A0 and A1: 3

...

only enable A1 and A3: a

...

enable all A0 to A3: f

Best, ilmenator

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Ah my mistake, I was reading the pin numbers in place of the binary columns (for lack of better words).

J5A.A0 - 1

J5A.A1 - 2

J5A.A2 - 3

J5A.A3 - 4

J5B.A4 - 5

etc
instead of
J5A.A0 - 1

J5A.A1 - 2

J5A.A2 - 4

J5A.A3 - 8

J5B.A4 - 16

etc

Thanks for both of your replies. :) Obvious after all!

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