Underskor Posted December 7, 2011 Report Posted December 7, 2011 (edited) Might be really obvious but it's not clicking for me. // bit mask to enable channels // // Pin mapping on MBHP_CORE_STM32 module: // 15 14 13 12 11 10 9 8 // J16.SO J16.SI J16.SC J16.RC J5C.A11 J5C.A10 J5C.A9 J5C.A8 // 7 6 5 4 3 2 1 0 // J5B.A7 J5B.A6 J5B.A5 J5B.A4 J5A.A3 J5A.A2 J5A.A1 J5A.A0 // // Examples: // mask 0x000f will enable all J5A channels // mask 0x00f0 will enable all J5B channels // mask 0x0f00 will enable all J5C channels // mask 0x0fff will enable all J5A/B/C channels // (all channels are disabled by default) #define MIOS32_AIN_CHANNEL_MASK 0x0000 If 0x000f is 15, how does that relate to J5A.A0..A3? Thanks in advance, Tom Edited December 7, 2011 by Underskor Quote
findbuddha Posted December 7, 2011 Report Posted December 7, 2011 Not sure where you got 15 from? My interpretation is: 0x0CBA Replace the letter with 0 if you want it disabled, f for enabled. They are groups of 4 channels (eg. A0... A3) Quote
Underskor Posted December 7, 2011 Author Report Posted December 7, 2011 (edited) 0x000f in decimal/base10 is 15. The reason I ask is because I'd like to disable all but the first mux (J5A.A0) so I only need to ground 7 inputs while troubleshooting/configuring. Edited December 7, 2011 by Underskor Quote
ilmenator Posted December 7, 2011 Report Posted December 7, 2011 It should be like this for A3...A0: only enable A0: 1 only enable A1: 2 only enable A2: 4 only enable A3: 8 only enable A0 and A1: 3 ... only enable A1 and A3: a ... enable all A0 to A3: f Best, ilmenator Quote
Underskor Posted December 7, 2011 Author Report Posted December 7, 2011 Ah my mistake, I was reading the pin numbers in place of the binary columns (for lack of better words). J5A.A0 - 1 J5A.A1 - 2 J5A.A2 - 3 J5A.A3 - 4 J5B.A4 - 5 etc instead of J5A.A0 - 1 J5A.A1 - 2 J5A.A2 - 4 J5A.A3 - 8 J5B.A4 - 16 etc Thanks for both of your replies. :) Obvious after all! Quote
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