cosmosuave Posted January 13, 2014 Report Share Posted January 13, 2014 I have planned to power my LPC Module with J2 5v from a mini ATX PS instead of USB... As mentioned below I cannot find IC3 on the board is it suppose to menan IC6 as this is 7805 voltage regulator... When I apply 5v to J2 the LCD's pulse off and on and work properly when supplied via USB (J17 jumper installed) Thanks... Brian For Jumper J2... When used as +5V input: for supplying the core from an external stabilized Power Supply Unit (PSU). The voltage regulator (IC3) doesn't need to be connected, also the rest of the voltage stabilization circuit between J1 and J2 (X1, C8, C9) can be left out. If the core module (and all connected modules to this branch) drains more than 100 mA, it's recommended to mount C8 directly to J2 (a small cable between the outer soldering pads of the left-out 7805 will do this) Quote Link to comment Share on other sites More sharing options...
novski Posted January 13, 2014 Report Share Posted January 13, 2014 Yes correct. The its IC6 and you have to make a bridge between Pin 1 to Pin 3 of IC6 (7805) to stabilize the 5V. Please don't connect Pin 2!!! Quote Link to comment Share on other sites More sharing options...
cosmosuave Posted January 13, 2014 Author Report Share Posted January 13, 2014 Thanks I figured IC6 but just wanted to verify and extra thanks for the schematic... Quote Link to comment Share on other sites More sharing options...
cosmosuave Posted January 20, 2014 Author Report Share Posted January 20, 2014 (edited) Removed IC6 and replaced it with a jumper but still getting the pulsing on and off with the LCDs... Should I remove all this as well "also the rest of the voltage stabilization circuit between J1 and J2 (X1, C8, C9) can be left out. " Just a note my voltage supply is 5v from a micro ATX PS and my meter is reading 5v from it... Think I toasted my PS as it arced out on it's case now I am not getting any voltage... Arrrrggghhh why did choose to make this non USB powered with the CV/gate board... I do not want to use 2 seperate power supplies for this... Surely someone here has done what I am trying to do... Sorry frustrated at the moment... Edited January 20, 2014 by cosmosuave Quote Link to comment Share on other sites More sharing options...
novski Posted January 20, 2014 Report Share Posted January 20, 2014 I can't follow. I think a ATX PS has 5&12V but i don't understand why you need 12V for a SEQ. Or maybe you meen the 3.3V? Please describe a litte more what you whant to do... Quote Link to comment Share on other sites More sharing options...
cosmosuave Posted January 20, 2014 Author Report Share Posted January 20, 2014 Yes you are correct... The reason for the ATX supply is that I require +/- 12v for the AOUT module that I am installing... Will busy today researching DIY PS which may be my better option... Quote Link to comment Share on other sites More sharing options...
cosmosuave Posted January 20, 2014 Author Report Share Posted January 20, 2014 (edited) Gonna go with this diy power supply and add a LM7809 with a smoothing cap to the +12 v rail to supply 9v to the core (J1) and will use a 15VAC transformer instead of a wall wart... Edited January 20, 2014 by cosmosuave Quote Link to comment Share on other sites More sharing options...
cosmosuave Posted March 3, 2014 Author Report Share Posted March 3, 2014 Need some help on this.... I just got a new PS and I am supplying the core board with 5v... Upon start up I got the blinking led on the expresso board and the LCD's display but dimly when the contrast and brightness adjusted this is when I removed IC6 (7805) and jumpered pin1 to pin3 ... Also notes say to do the following.... When used as +5V input: for supplying the core from an external stabilized Power Supply Unit (PSU). The voltage regulator (IC3) doesn't need to be connected, also the rest of the voltage stabilization circuit between J1 and J2 (X1, C8, C9) can be left out. If the core module (and all connected modules to this branch) drains more than 100 mA, it's recommended to mount C8 directly to J2 (a small cable between the outer soldering pads of the left-out 7805 will do this) I removed X1 and now when I apply the 5v at J1 nothing powers up... Do I need to remove those other components as mentioned? I am hitting a roadblock with this and need to get past so I can focus on the AOUT and control surface... It is all good when powered via USB but I do not plan to use the sequencer with a computer... I keep soldering and desoldering parts and eventually I will have no pads to solder to... Appreciate some guidance... Thanks... bri Quote Link to comment Share on other sites More sharing options...
Shuriken Posted March 3, 2014 Report Share Posted March 3, 2014 J2: When used as +5V input: for supplying the core from an external stabilized Power Supply Unit (PSU). The voltage regulator (IC6) doesn't need to be connected, also the rest of the voltage stabilization circuit between J1 and J2 (X1, C8, C9) can be left out. If the core module (and all connected modules to this branch) drains more than 100 mA, it's recommended to mount C8 directly to J2 (a small cable between the outer soldering pads of the left-out 7805 will do this). So you need to apply the voltage to J2 and not J1. J1 is directly connected to X1, so it does make sense that you don't get any power up. Also you do not need to remove components. You could have just left them as is. It only states you can leave them out (to save on components). Quote Link to comment Share on other sites More sharing options...
cosmosuave Posted March 3, 2014 Author Report Share Posted March 3, 2014 J2 - It was clearly stated and for some reason my brain kept thinking J1... Thank you so much as this works now when I apply 5v to J2... Now I can move on... Quote Link to comment Share on other sites More sharing options...
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.