Mr modnaR Posted August 22, 2006 Report Share Posted August 22, 2006 ok, i'm going to use a transformer with two 115VAC inputs, and two 6VAC outputs. as i have 240VAC here in the UK, i assume i need to commect the two 'inner' input pins and connect the 250V across the two outer pins, correct?then, to get both 6VAC and 12VAC from the trafo, i need to short the 'inner' pins of the output pins and use the two outer pins for 12VAC and use the shorted connection and one of the outer pins for 6VAC. is that correct?also to rectify the AC, would i then need two rectifiers, or would one do, as in the PSU designs of NorthernLightX and Altitude?many thanks for any help given. Quote Link to comment Share on other sites More sharing options...
Mr modnaR Posted August 24, 2006 Author Report Share Posted August 24, 2006 ok, here's the schematic, please excuse the poor eagle skills!anyone see any problems with that design? i'm going to leave the caps and regulators in place on the SID boards. cheers. Quote Link to comment Share on other sites More sharing options...
Altitude Posted August 25, 2006 Report Share Posted August 25, 2006 I would add some caps after the regulators (10 uF electrolytic and 100 nf)I definitely like the dual secondary idea though and for the normal MBHP stuff that does not need the -12, this is the way to goI would look up how the ground is referenced though since i'm not sure how that applies in a half wave/ bridged mixmight want to read this:http://sound.westhost.com/power-supplies.htm Quote Link to comment Share on other sites More sharing options...
Mr modnaR Posted September 3, 2006 Author Report Share Posted September 3, 2006 thanks for the tip about the extra caps. this design seems to work well. fitted all the bits onto stripboard. took up 11tracks x 21 holes: quite compact! getting a stable 15V and 5V, though i've yet to try it on the 4 cores and SIDs. will keep you posted.@Altitude, can you not get hold of a 4 output 24V transformer, each with 6V? that way you could bridge a few, and make 12V, 5V and -12V quite easily. feeding the 7805 with ~7V (that's around 7V not 7VAC!) makes it run cool, which is a load off my mind! cheers for all the input! Quote Link to comment Share on other sites More sharing options...
tatapoum Posted September 4, 2006 Report Share Posted September 4, 2006 This design of rectifier is not good at all. The fact is that the half of the bridge is parallelized by joining the both ground. This induces an incorrect signal and generate a lot of buzz.The best design is too put the 7805 after the 7815. But this requires a big voltage drop in the the 7805. Don't forget to mount a heat sink.Ludo Quote Link to comment Share on other sites More sharing options...
Mr modnaR Posted September 4, 2006 Author Report Share Posted September 4, 2006 i'm sorry, i don't understand what you mean by 'half the bridge is parallelised' ???i read 12VAC across the two outer pins on the trafo, and 6VAC from the the middle to either outer pin. that was my logic: to get 6VAC and 12VAC from one trafo, so that the 7805 wouldn't have to do as much work. is there a way to do it with that trafo? Quote Link to comment Share on other sites More sharing options...
tatapoum Posted September 4, 2006 Report Share Posted September 4, 2006 If you link the ground, you can see that a part of both rectifiers are redundant. This results in a bad rectification that injects a lot of noise.ludo Quote Link to comment Share on other sites More sharing options...
Mr modnaR Posted September 4, 2006 Author Report Share Posted September 4, 2006 link the ground? it's AC, there is no ground, correct? or do you mean the centre two output pins on the transformer? still confused... Quote Link to comment Share on other sites More sharing options...
tatapoum Posted September 4, 2006 Report Share Posted September 4, 2006 Ground is 0V in the DC part of the circuit. I think you will link them.ludo Quote Link to comment Share on other sites More sharing options...
Mr modnaR Posted September 4, 2006 Author Report Share Posted September 4, 2006 i see, no i'm keeping them separate, or is that not a good idea? Quote Link to comment Share on other sites More sharing options...
lylehaze Posted September 4, 2006 Report Share Posted September 4, 2006 Normally all the 0V connections would be joined,and they probably HAVE to be if they are workingfor the same project.Connecting them in your drawing would bring bad things. Quote Link to comment Share on other sites More sharing options...
Mr modnaR Posted September 4, 2006 Author Report Share Posted September 4, 2006 ok, i'm completely new to all this eletronical malarkey, so please treat me as a newbie, because that's what i am! why would the grounds HAVE to be connected? and why, if they were to be connected, would that bring bad things?i appreciate the input, thank you. Quote Link to comment Share on other sites More sharing options...
lylehaze Posted September 4, 2006 Report Share Posted September 4, 2006 OK, now I've switched over to my better browser.I'll do my best to answer your questions, and Iwelcome anyone to jump in and correct me.In most DC electric systems, including the kind ofcircuits we play with here, all voltages are measuredagainst a common reference, often called Zero Voltsor even ground (whether or not it's really grounded).so +5 Volts means 5 volts above 0V, and -12 volts wouldbe 12 volts below. IF both have the same 0V reference,then you'd expect to see about 17 volts between them.(The difference between +5 and -12 is 17)However, if these two voltages are "isolated"(not sharingany common reference), then there could be ANY difference beween them. even 2000 volts would easily be possible.Obviously this could be hazardous to IC's that have anupper voltage limit.Now back to your drawing.There are two separate secondaries on the transformer.In your drawing, they are joined (between S1 and S2)This means that they are not isolated. They are connected inSeries. This is fine.. so far.Now we add a bridge to create DC, powered from the sum of the secondaries, S1+S2. Cool. Higher voltage.We add another bridge, but it's only using S2. That works,but the 0V connection we have created is now higher thanthe 0V of the first supply (by the voltage in S1)Now out in the final application, all the 0V lines will be connected together, as the "universal common return"if you'll forgive my description.Now, because the 0V connections have been joined, BOTHsides of the S1 primary are just one diode away from thesame potential. in short, you've shorted your secondary.Suddenly current consumption goes up, lots of heat gets generated, and the beautiful supply goes into theatricalmeltdown mode.My explanation is a compromise, due to me trying to benon-technical, or possibly to me being completely wrong.If some reader is laughing at how stupidly I've described the problem, PLEASE jump right in and do a better job.Also, I offer this to help, not to criticize. I'm new here, andif I'm not helping then I'll just shut the *&^% up.Good Luck,LyleHaze Quote Link to comment Share on other sites More sharing options...
Mr modnaR Posted September 4, 2006 Author Report Share Posted September 4, 2006 thanks for explaining that! your reasoning stands, i just measured just under 5V between the two grounds. :'(now what? can i not do it this way with this transformer? Quote Link to comment Share on other sites More sharing options...
lylehaze Posted September 4, 2006 Report Share Posted September 4, 2006 Actually,to be more accurate, I don't know that you'd have a meltdown.Perhaps I was being dramatic there.I am sure that it would generate a lot of unexpected noise in thepower supply. (noise being stuff you don't want mixed in withthe power you expected)If you are building an audio circuit, you'll want the cleanest, purestpower supply you can get. I'm building one now with-8V, -5V, +5V, +8V for the analog stuff, and another +5 digital topower a core board and VFD.Even though I want to keep the digital +5 apart from the analogsupplies, they all MUST have a common ground, or it just won't work.How much current do you need on each supply?Good Luck,LyleHaze Quote Link to comment Share on other sites More sharing options...
Mr modnaR Posted September 4, 2006 Author Report Share Posted September 4, 2006 in NorthernLightX's psu:the centre pin of his dual 12V transformer is used as ground. is this what i need to do with the first pin of s1 to give me 12VAC and 6VAC?i need enough to power 4xCores and 4xSIDs and 1xLED Backlight and Control Surface C! in recent tests, Altitude measure this lot pulling around 500mA, i would like around 1000mA if possible.thank you for your help. Quote Link to comment Share on other sites More sharing options...
lylehaze Posted September 4, 2006 Report Share Posted September 4, 2006 Ouch.I just reviewed your earlier posts, we may have another problem..You connect the secondaries in series, get 12VAC.You rectify that to DC, you get (12 * 1.4) VDC - (2 * Diode vF)There is a small "forward voltage drop" across any diode in conduction.Even with "perfect" diodes you only get 16.8 volts (no load) available.What's the minimum input voltage of your 7815?You are dangerously close to starving that regulator.Or maybe I just screwed up the math, I do software better than hardware.LyleHaze Quote Link to comment Share on other sites More sharing options...
Mr modnaR Posted September 4, 2006 Author Report Share Posted September 4, 2006 yes i think you're right, maybe i should chuck a 7812 in there, and bridge the regulators on the sid boards?what do you reckon on using the first transformer pin as ground then using a rectifier to give 12VAC and 6VAC above that? does that work? Quote Link to comment Share on other sites More sharing options...
lylehaze Posted September 4, 2006 Report Share Posted September 4, 2006 If you're only doing positive voltages, I would do it like this:Keep S1 and S2 connected in series, like before.Use a single bridge rectifier, from the bottom of S1 to the top of S2 (12 VAC)Ground the negative side of the bridge rectifier (0V for all voltages)Big capacitor from bridge V+ to 0V (smoothing the DC)Use positive regulators from there, with the option of a dropping resistor if the heat is too great.Use heatsinks. They're cheap. positive regulators may be attached directly to a metal case (0V)Also, you may use multiple 7805's to spread the heat load.Sorry, no means for artwork today, I'm too lazy.What's next?LyleHaze Quote Link to comment Share on other sites More sharing options...
Mr modnaR Posted September 4, 2006 Author Report Share Posted September 4, 2006 thanks for your suggestion. would something like this work?: Quote Link to comment Share on other sites More sharing options...
lylehaze Posted September 4, 2006 Report Share Posted September 4, 2006 OK, it dumped my first reply..What you're proposing is not ideal.If you ground at the transformer, you'll be creating both positive and negative voltages.Since you only need positive, that's a waste.Since you only need positive voltages, you should rectify it first, as I described previously.I REALLY hate working in windows, and now you've got me trying to draw with "paint".Warning: Ugly.. I mean REALLY ugly drawings are attached.You have been warned.LyleHaze Quote Link to comment Share on other sites More sharing options...
lylehaze Posted September 4, 2006 Report Share Posted September 4, 2006 After looking closer, your last drawing would be supplying the 7805 with negative voltage.This is outside the specs for the regulator, and would result in "bad things"Input voltage (at pin 1 of regulator) may not go below the GND reference at pin 2 of regulator.LyleHaze Quote Link to comment Share on other sites More sharing options...
Mr modnaR Posted September 4, 2006 Author Report Share Posted September 4, 2006 what i want however, is to get BOTH 6VAC and 12VAC from the transformer, with the idea of giving the 6VAC (rectified obviously) to the 7805 in order to save it from chewing up the extra volts when given the full transformer output. doing the whole 12VAC to 5VDC and 12VDC was what i tried initially, and the 7805 got hot too hot for my liking (don't worry i had it heatsinked!). Quote Link to comment Share on other sites More sharing options...
lylehaze Posted September 4, 2006 Report Share Posted September 4, 2006 Well, if you must, OK.GND the bottom of S1.Connect the top of S1 to the bottom of S2, and to the Anode of a diode. take the cathode of that diode to a filter capacitor as +VLowConnect the anode of another single diode to the top of S2. take the cathode of that diode to a filter capacitor as +VHigh.Each supply is now Half-Wave rectified. You'll need to double thesize of your transformer to supply the same current.You'll also need to more than double the size of your capacitors tocover the (over) 50% loss of power.There will be a LOT of ripple in this supply. I hope you're not usingit for anything that needs smooth power.Good Luck,LyleHaze Quote Link to comment Share on other sites More sharing options...
Mr modnaR Posted September 4, 2006 Author Report Share Posted September 4, 2006 no, i need smooth power unfortunately, grrr, seems like this plan didn't work. thank you for your patience and understanding.*returns to drawing board to weep slightly* Quote Link to comment Share on other sites More sharing options...
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